B32

a.

CH₂ClCOOH(aq) + NaOH(aq) → NaCH₂ClCOO(aq) + H₂O eller
CH₂ClCOOH + OH^– → CH₂ClCOO^– + H₂O

b.

\[n_\mathrm{CH_2ClCOOH}:n_\mathrm{NaOH} = 1:1 \Rightarrow n_\mathrm{NaOH} = n_\mathrm{CH_2ClCOOH} = 0,030 \mathrm{mol}\]

c.

\[\begin{aligned}V &= \frac {n_\mathrm{NaOH}}{c_\mathrm{NaOH}}  = \frac {0,030\mathrm{mol}}{1,037\mathrm{mol/dm^3}} = 0,02892960\mathrm{dm^3} ≈ \\ &≈ 0,029\mathrm{dm^3} = 29\mathrm{ml}\end{aligned}\]