a.
N2O4(g) ⇌ 2NO2(g)
\[\begin{aligned}K &= \frac {[\mathrm{NO_2}]^2}{[\mathrm{N_2O_4}]} \\ K[\mathrm{N_2O_4}] &= [\mathrm{NO_2}]^2 \\ [\mathrm{NO_2}] &= \sqrt{K[\mathrm{N_2O_4}]} = \sqrt{0,36\mathrm{M} \cdot 0,040\mathrm{M}} = \sqrt{0,0144\mathrm{M^2}} = \\ &= 0,12\mathrm{M}\end{aligned}\]
b.
N2O4(g) ⇌ 2NO2(g)
|
| [N2O4] | [NO2] |
|
| f.r. | \[x\] | \[0\] | M |
| ∆ | \[–0,060\] | \[+0,12\] | M |
| v.j. | \[0,040\] | \[0,12\] | M |
\[\begin{aligned}x - 0,060 &= 0,040 \\ x &= 0,040 + 0,060 = 0,10 \\ [\mathrm{N_2O_4}] &= 0,10\mathrm{M} \\ n_\mathrm{N_2O_4} &= [\mathrm{N_2O_4}] \cdot V = 0,10\mathrm{mol/dm^3} \cdot 1,0\mathrm{dm^3} = 0,10\mathrm{mol}\end{aligned}\]
