a
\[\begin{aligned} c_1V_1 &= c_2V_2 \\ c_2 &= \frac {c_1V_1}{V_2} = \frac {0,00500\frac {\mathrm{mol}}{\mathrm{dm^3}} \cdot 0,100\mathrm{dm^3}}{0,750\mathrm{dm^3}} = \\ &= 0,00066667\mathrm{mol/dm^3} ≈ 0,000667\mathrm{mol/dm^3}\end{aligned}\]
b
\[\begin{aligned} c_1V_1 &= c_2V_2 \\ c_2 &= \frac {c_1V_1}{V_2} = \frac {0,00500\frac {\mathrm{mol}}{\mathrm{dm^3}} \cdot 0,030\mathrm{dm^3}}{0,500\mathrm{dm^3}} = 0,00030\mathrm{mol/dm^3}\end{aligned}\]
Svavelsyran protolyseras fullständigt:
H2SO4(aq) → 2H+(aq) + \(\mathrm{SO_4^{2-}}\)(aq)
\[n_\mathrm{H_2SO_4}:n_\mathrm{H^+} = 1:2 \\ \mathrm{[H^+]} = 2c_\mathrm{H_2SO_4} = 2 \cdot 0,00030\mathrm{mol/dm^3} = 0,00060\mathrm{mol/dm^3}\]
c.
\[\begin{aligned} c_1V_1 &= c_2V_2 \\ c_2 &= \frac {c_1V_1}{V_2} = \frac {0,00500\frac {\mathrm{mol}}{\mathrm{dm^3}} \cdot 0,025\mathrm{dm^3}}{1,00\mathrm{dm^3}} = 0,000125\mathrm{mol/dm^3}\end{aligned}\]
Svavelsyran protolyseras fullständigt:
H2SO4(aq) → 2H+(aq) + \(\mathrm{SO_4^{2-}}\)(aq)
\[n_\mathrm{H_2SO_4}:n_\mathrm{H^+} = 1:2 \\ \mathrm{[H^+]} = 2c_\mathrm{H_2SO_4} = 2 \cdot 0,000125\mathrm{mol/dm^3} = 0,00025\mathrm{mol/dm^3} \\ \mathrm{pH} = -\lg[\mathrm{H^+}] = -\lg0,00025 = 3,60205999 ≈ 3,60\]
