a
\[n_\mathrm{H_2O} = \frac {m_\mathrm{H_2O}}{M_\mathrm{H_2O}} = \frac {18\mathrm{g}}{(1,008 \cdot 2 + 16,00)\frac {\mathrm{g}}{\mathrm{mol}}} = 0,99911190\mathrm{mol} ≈ 1,0\mathrm{mol}\]
Svar: \(n_\mathrm{H_2O} = 1,0\mathrm{mol}\)
b
\[n_\mathrm{He} = \frac {m_\mathrm{He}}{M_\mathrm{He}} = \frac {20,0\mathrm{g}}{4,003\frac {\mathrm{g}}{\mathrm{mol}}} = 4,99625281\mathrm{mol} ≈ 5,00\mathrm{mol}\]
Svar: \(n_\mathrm{He} = 5,00\mathrm{mol}\)
c
\[\begin{aligned} n_\mathrm{C_{12}H_{22}O_{11}} &= \frac {m_\mathrm{C_{12}H_{22}O_{11}}}{M_\mathrm{C_{12}H_{22}O_{11}}} = \frac {6,05\mathrm{g}}{(12,01 \cdot 12 + 1,008 \cdot 22 + 16,00 \cdot 11)\frac {\mathrm{g}}{\mathrm{mol}}} = \\ &= 0,01767476\mathrm{mol} ≈ 0,0177\mathrm{mol}\end{aligned}\]
Svar: \(n_\mathrm{C_{12}H_{22}O_{11}} = 0,0177\mathrm{mol}\)
d
\[n_\mathrm{Fe} = \frac {m_\mathrm{Fe}}{M_\mathrm{Fe}} = \frac {25,0 \cdot 10^3 \mathrm{g}}{55,85\frac {\mathrm{g}}{\mathrm{mol}}} = 447,627574\mathrm{mol} ≈ 448\mathrm{mol}\]
Svar: \(n_\mathrm{Fe} = 448\mathrm{mol}\)
e
\[n_\mathrm{Fe_3O_4} = \frac {m_\mathrm{Fe_3O_4}}{M_\mathrm{Fe_3O_4}} = \frac {2,0 \cdot 10^6\mathrm{g}}{(55,85 \cdot 3 + 16,00 \cdot 4)\frac {\mathrm{g}}{\mathrm{mol}}} = 8637,44332\mathrm{mol} ≈ 8,6 \cdot 10^3\mathrm{mol}\]
Svar: \(n_\mathrm{Fe_3O_4} = 8,6 \cdot 10^3\mathrm{mol}\)
