NiSO4 · xH2O(s) \( \overset{\Delta}\rightarrow\) NiSO4(s) + xH2O(g)
\[\begin{aligned} n_\mathrm{NiSO_4} &= \frac {m_\mathrm{NiSO_4}}{M_\mathrm{NiSO_4}} = \frac {0,590\mathrm{g}}{(58,69+32,07+16,00 \cdot 4)\mathrm{g/mol}} = \\ &= 0,00381235\mathrm{mol} \\ m_\mathrm{H_2O} &= m_\mathrm{NiSO_4 \cdot xH_2O} - m_\mathrm{NiSO_4} = 1,00\mathrm{g} - 0,590\mathrm{g} = 0,410\mathrm{g} \\ n_\mathrm{H_2O} &= \frac {m_\mathrm{H_2O}}{M_\mathrm{H_2O}} = \frac {0,410\mathrm{g}}{(1,008 \cdot 2 + 16,00)\mathrm{g/mol}} =0,02275755\mathrm{mol} \\ x &= \frac {n_\mathrm{H_2O}}{n_\mathrm{NiSO_4}} = \frac {0,02275755\mathrm{mol}}{0,00381235\mathrm{mol}} = 5,96942078 ≈ 6\end{aligned}\]
Svar: NiSO4 · 6H2O(s)
