a.
\[c = \frac {1\mathrm{matsked}}{3,0\mathrm{l}} = \frac {1}{3}\mathrm{matsked/l}\]
b.
\[c = \frac {m}{V} = \frac {22\mathrm{g}}{3,0\mathrm{dm^3}} = 7,33333333\mathrm{g/dm^3} ≈ 7,3\mathrm{g/dm^3}\]
c.
\[c = \frac {m}{V} = \frac {22\mathrm{g}}{3000\mathrm{ml}} = 0,00733333 ≈ 0,73\%\]
d.
\(c_\mathrm{NaCl} = \frac {n_\mathrm{NaCl}}{V}\)
\[n_\mathrm{NaCl} = \frac {m_\mathrm{NaCl}}{M_\mathrm{NaCl}} = \frac {22\mathrm{g}}{(22,99+35,45)\frac {\mathrm{g}}{\mathrm{mol}}} = 0,37645448\mathrm{mol}\]
\(c_\mathrm{NaCl} = \frac {0,37645448\mathrm{mol}}{3,0\mathrm{dm^3}} = 0,12548483\mathrm{mol/dm^3} ≈ 0,13\mathrm{M}\)
