Salpetersyran neutraliseras:
HNO3(aq) + NaOH(aq) → H2O + NaNO3(aq)
\[n_\mathrm{HNO_3} = c_\mathrm{HNO_3} \cdot V_\mathrm{HNO_3} = 0,152\frac {\mathrm{mol}}{\mathrm{dm^3}} \cdot 0,0250\mathrm{dm^3} = 0,00380\mathrm{mol}\]
\[n_\mathrm{HNO_3}:n_\mathrm{NaOH} = 1:1 \\ n_\mathrm{NaOH} = n_\mathrm{HNO_3} = 0,00380\mathrm{mol}\]
\[V_\mathrm{NaOH} = \frac {n_\mathrm{NaOH}}{c_\mathrm{NaOH}} = \frac {0,00380\mathrm{mol}}{0,100\frac {\mathrm{mol}}{\mathrm{dm^3}}} = 0,0380\mathrm{dm^3} = 38,0\mathrm{ml}\]
